# Find the norton equivalent at terminals a b of the circuit in the following figure if r 26 ω

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NOTE: In order to do a source transformation, the terminals at the end of the source (like a and b in the attached circuit) should have the same v-i relation. For example, if the sources are turned off in the circuit, the equivalent resistance is R. Oct 02, 2019 · Image Transcriptionclose. For the circuit below: (A) Determine the Thevenin equivalent (vs with reference on top) (B) Determine the Norton equivalent (ig with arrow pointing up) 5ix оа 100 mA ix 7.5 kQ 250 Ω Ob Remove the 2 Ω resistor from the circuit shown in Figure P8-3 and find the Norton equivalent circuit with respect to the open terminals. Let R = 1 Ω. 11. Remove the 1/2 Ω resistor from the circuit shown in Figure P8-6 and find the Norton equivalent circuit with respect to the open terminals. Let R = 1 Ω. 12. 4- Find the Norton equivalent circuit at terminals (a,b). [I N=6A, R N=20/3Ω] 5- A linear circuit is connected to a variable resistor. An ideal ammeter (with zero internal resistance) and an ideal voltmeter (with infinite internal resistance) are used to measure the voltage and the current as shown in the figure. The results of Problem 3.66 The circuit in Fig. P3.66 is to be connected to a load resistor RL between terminals (a,b). (a) Find the Thevenin equivalent circuit at terminals´ (a,b). (b) Choose RL so that the current ﬂowing through it is 0.5 A. 4 Ω 6 Ω 8 Ω 4 Ω 10 Ω 4 A 48 V c d a b +_ Voc + _ I1 I 2 I3 Figure P3.66: Circuit for Problems 3.66 and 3.67 ... b 10 RTH=5+20=25 Ω n Find the Thevenin’s equivalent circuit of the circuit shown below, to the left of the terminals a-b. Then find the current through RL = 6, 16, and 36 Ω. Example 4.7.3 4.7 Thevenin’s Theorem C.T. Pan 36 The resistance between terminals a and b in the figure is 75 Ω. If the resistors labeled R have the same value, determine R. Nov 28, 2019 · We can find the current IL which is flowing through the load resistance RL in any Thevenin equivalent circuit. IL=Vth/Rth+RL. This identity is nothing But Ohm’s law {I=V/R}. Here RL is the load resistance which to say that finds the value in any question. Now we go to steps that help us to solve the numerical question of Thevenin theorem. 4. After the circuit below has been in operation for a long time, a is screwdriver inadvertently connected across the terminals a, b. Assume the resistance of the screwdriver is negligible. a) Find the current in the screwdriver at t =0+ and t =∞. b) Derive the expression for the current in the screwdriver for t ≥0+. Let’s take a look at an example circuit and calculate the current flowing through a load resistor between two terminals. The process for analyzing a DC circuit using Thevenin’s Theorem requires the following steps: Find the Thevenin Resistance by removing all voltage sources and load resistor. Find the Thevenin Voltage by plugging in the ... Find the Norton equivalent at terminals a-b of the circuit in Fig. 4.119. Step-by-step solution: 100 %(18 ratings) Find the Norton equivalent at terminals a-b of the circuit in Fig. 4.119. Step-by-step solution: 100 %(18 ratings) Mar 14, 2018 · No. You get I3*R3=3.57V when you 'short circuit' the terminals A and B and V AB =0 in that çase. Do you know the steps for finding the Thevenin equivalent of a network? It looks like you are mixing Thevenin and Norton without knowing the fundamental differences between them. It states that a linear two‐terminal circuit (Fig. a) can be replaced by an equivalent circuit (Fig. b) consisting of a current source I N in parallel with a resistor R N, (a) (b) where I N is the short‐circuit current through the terminals. R N is the input or equivalent resistance at the terminals when the indepen. sources are turned off. Determine the Norton equivalent at terminals a-b for the circuit in Fig. 4.115. Figure 4.115 Solution. To get R Th , we can inject 1 A at the terminals as shown Fig. (a). Nov 30, 2012 · Remove section of the network where to find the Norton equivalent circuit and mark clearly the two terminals as a-b b. Determine the Norton equivalent resistance seen from the terminal a-b with independent sources is turn off c. Get the Norton current value of current flowing through the terminals a-b when a short circuit in the terminal. Norton equivalent I N R N some circuit load + – v RL load + – v RL Ideas developed independently (Thevenin in 1880’s and Norton in 1920’s). But we recognize the two forms as identical because they are source transformations of each other. In EE 201, we won’t make a distinction between the methods for ﬁnding Thevenin and Norton. Find ... The total current through the short between the load connection points is the sum of these two currents: 7 amps + 7 amps = 14 amps. This figure of 14 amps becomes the Norton source current (I Norton) in our equivalent circuit: Find Norton Resistance. Remember, the arrow notation for current source points in the direction of conventional current ... Find the short circuit current between these terminals. This is the Norton equivalent current, I N. Now turn off all sources. Replace each source with its characteristic resistance. (Ideal voltage sources R = 0, a short circuit. Ideal current sources R = ∞, an open circuit.) Find the resistance across the terminals. This is the source ... Answer to Find the Thevenin equivalent between terminals a-bof the circuit in Fig. 4.120.. Let’s take a look at an example circuit and calculate the current flowing through a load resistor between two terminals. The process for analyzing a DC circuit using Thevenin’s Theorem requires the following steps: Find the Thevenin Resistance by removing all voltage sources and load resistor. Find the Thevenin Voltage by plugging in the ... 4. Draw the Thevenin equivalent circuit with the marked terminals Example: Find the Thevenin circuit of a and b terminals for for the following network. 12 6A 36V 3 6 VTh RTh Step 2. 12 3 6 =+=Ω + =+ 3 4 7 6 12 (6)(12) RTh 3 Step 3: Use superposition. For the 36 V source we can apply the voltage divider rule a b RTh If the 10V source of e.m.f. is removed from Figure (b) the resistance ‘looking-in’ at a break made between A and B is given by: r = 2 × 8/2 + 8 = 1.6 Ω. From the Norton equivalent network shown in Figure(d) the current in the 10 Ωresistance, by current division, is given by: I = (1.6/1.6 + 5 + 10) (5) = 0.482A. as obtained previously in ... Find the maximum power that can be delivered to the load resistor R L of the circuit shown in the following figure. Step 1 − In Thevenin’s Theorem chapter, we calculated the Thevenin’s equivalent circuit to the left side of terminals A & B. We can use this circuit now. It is shown in the following figure. Determine the Norton equivalent at terminals a-b for the circuit in Fig. 4.115. Figure 4.115 Solution. To get R Th , we can inject 1 A at the terminals as shown Fig. (a). Problem 3.73 Find the Norton equivalent circuit at terminals (a,b) for the circuit in Fig. P3.73. 0.2 Ω 0.2 Ω 0.1 Ω 0.25 Ω a b I0 0.2I0 Iex Vex + _ I1 I2 I3 +_ Figure P3.73: Circuit for Problem 3.73. Solution: The circuit contains no independent sources. Hence, VTh =0. To determine RTh, we add an external voltage source Vex and proceed to ... Nov 28, 2019 · We can find the current IL which is flowing through the load resistance RL in any Thevenin equivalent circuit. IL=Vth/Rth+RL. This identity is nothing But Ohm’s law {I=V/R}. Here RL is the load resistance which to say that finds the value in any question. Now we go to steps that help us to solve the numerical question of Thevenin theorem. If the 10V source of e.m.f. is removed from Figure (b) the resistance ‘looking-in’ at a break made between A and B is given by: r = 2 × 8/2 + 8 = 1.6 Ω. From the Norton equivalent network shown in Figure(d) the current in the 10 Ωresistance, by current division, is given by: I = (1.6/1.6 + 5 + 10) (5) = 0.482A. as obtained previously in ... Find the Norton equivalent at terminals a-b of the circuit in Fig. 4.119. Step-by-step solution: 100 %(18 ratings) Example: 1. Find Norton’s equivalent circuit for the network shown in the figure 1 at the left of terminals 1-2. Assume I = 5∠ 0 o A. If the 10V source of e.m.f. is removed from Figure (b) the resistance ‘looking-in’ at a break made between A and B is given by: r = 2 × 8/2 + 8 = 1.6 Ω. From the Norton equivalent network shown in Figure(d) the current in the 10 Ωresistance, by current division, is given by: I = (1.6/1.6 + 5 + 10) (5) = 0.482A. as obtained previously in ... NOTE: In order to do a source transformation, the terminals at the end of the source (like a and b in the attached circuit) should have the same v-i relation. For example, if the sources are turned off in the circuit, the equivalent resistance is R. The resistance between terminals a and b in the figure is 75 Ω. If the resistors labeled R have the same value, determine R. Min H. Kao Department of Electrical Engineering & Computer ...